refactoring source tree

refactored sources into directory per binary in order to prepare for moving more complex, multi-file, programs onto source tree
This commit is contained in:
Tom Everett
2019-10-18 16:39:18 -06:00
parent 37a3e77dee
commit ac1c46e29b
21 changed files with 38 additions and 38 deletions
+104
View File
@@ -0,0 +1,104 @@
" cp: cp file1 file2 [file3 file4 [file5 file6] ...]
"
" Copies in pairs: file1 to file2, file3 to file4 etc.
lac 017777 " Skip past argc and save
tad d1 " argv[0] (our name) into name2
dac name2 " We will skip past it later
loop:
lac 017777 i " Any arguments left?
sad d4
sys exit " 4 words = no args left, exit
sad d8 " Do we have 2 args?
jmp unbal " No, an unbalanced set of arguments
tad dm8 " Subtract 8 (two args) from the argc
dac 017777 i " and save it
lac name2
tad d4
dac name1 " Skipping pairs of filenames? not sure
tad d4
dac name2
sys open; name1: 0; 0 " Open the input file
spa
jmp error " File open error
lac o17 " Why load 15 (017) into AC?
sys creat; name2: 0 " Create the output file
spa
jmp error " File create error
dzm nin " Set the number of input words to zero
1:
lac bufp " Set up the base of the upcoming read
tad nin " to be the buffer + nin so we skip
dac 0f " the existing words in the buffer
-1
tad nin " Calculate 1024 - nin, i.e. the number
cma " of empty words yet to be filled in the
tad d1024 " buffer, and use it as the read count
dac 0f+1
lac d2 " Read from fd 2: hard-wired in fd!
sys read; 0:..;..
sna
jmp 2f " No words were read in, go to 2f
tad nin " Add the number of words read in
dac nin " to the existing number of words
sad d1024
jmp 2f " We do have 1,024 words, go to 2f
jmp 1b " Loop back if we don't have 1,024 words
2:
lac nin " Load the number of words in the input buffer
dac 2f " Save in the write word count argument
lac d3 " Write to fd 3: hard-wired out fd!
sys write; buf; 2:0
dzm nin " Set nin back to zero
lac 2b " Get the write count (updated by sys write)
sad d1024 " Did we write the buffer out?
jmp 1b " Yes, we wrote 1,024 words, so loop back
" to read another buffer's worth
lac d2
sys close " Close fd 2 and fd 3
lac d3
sys close
jmp loop " Loop back to deal with the next arguments
error: " File error, print out the name1 on
lac name1 " standard output, fd 1 followed by " ?\n"
dac 1f
lac d1
sys write; 1:0; 4
lac d1
sys write; mes; 1
lac name2 " Then do the same with name 2
dac 1f
lac d1
sys write; 1: 0; 4
lac d1
sys write; mes; 2
jmp loop " Loop back to deal with the next arguments
mes:
040000;077012 " String literal: " ?\n"
unbal: " We had an unbalanced set of arguments
lac name2 " so print out the name after name2
tad d4 " on standard output followed by " ?\n"
dac 1f
lac d1
sys write; 1: 0; 4
lac d1
sys write; mes; 2
sys exit
d1: 1 " Numeric constants
d2: 2
d3: 3
d4: 4
d8: 8
o17: 017
dm8: -8
d1024: 1024
nin: 0 " Number of words in the input buffer
bufp: buf " Pointer to the buffer
buf: .=.+1024 " Buffer of 1,024 words